The kinetic energy acquired by a mass $m$ in travelling a certain distance $d$ starting from rest under the action of a constant force is directly proportional to
$\sqrt m $
Independent of $ m$
$1/\sqrt m $
$m$
If a man increase his speed by $2 \,m/s$ , his K.E. is doubled, the original speed of the man is
The kinetic energy of a body of mass $3 \,kg$ and momentum $2 \,N-s$ is
Two identical uniform discs roll without slipping on two different surfaces $AB$ and $CD$ (see figure) starting at $A$ and $C$ with linear speeds $v _1$ and $v _2$, respectively, and always remain in contact with the surfaces. If they reach $B$ and $D$ with the same linear speed and $v_1=3 \ m / s$, then $v_2$ in $m / s$ is $\left(g=10 \ m / s ^2\right)$
The same retarding force is applied to stop a train. The train stops after $80 m$. If the speed is doubled, then the distance will be
If the kinetic energy of a body increases by $0.1\%$, the percent increase of its momentum will be .............. $\%$