The kinetic energy of a body decreases by 36% | vedclass

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Question

(b) $P = \sqrt {2\,mE} $  $	herefore P \propto \sqrt E $

In given problem $K.E.$ becomes $64\%$ of the original value.

$\frac{{{P_2}}}{{{P

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(b) $P = \sqrt {2\,mE} $  $	herefore P \propto \sqrt E $

In given problem $K.E.$ becomes $64\%$ of the original value.

$\frac{{{P_2}}}{{{P_1}}} = \sqrt {\frac{{{E_2}}}{{{E_1}}}} = \sqrt {\frac{{64E}}{{100E}}} = 0.8$==>${P_2} = 0.8\,P$

$	herefore {P_2} = 80\% $ of the original value.

i.e. decrease in momentum is $20\%$.

The kinetic energy of a body decreases by $36\%$. The decrease in its momentum is ............... $\%$

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