If kinetic energy of a body is increased by 300% than percentage change in momentum will be

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5.Work, Energy, Power and Collision

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If kinetic energy of a body is increased by $300\%$ than percentage change in momentum will be

A

$100$

B

$150$

C

$\sqrt {300} $

D

$175$

(AIPMT-2002)

Solution

(a)Let initial kinetic energy, ${E_1} = E$

Final kinetic energy, ${E_2} = E + 300\% $ of $E = 4E$

As $P \propto \sqrt E $

==>$\frac{{{P_2}}}{{{P_1}}} = \sqrt {\frac{{{E_2}}}{{{E_1}}}} = \sqrt {\frac{{4E}}{E}} = 2$

==> ${P_2} = 2{P_1}$

==>${P_2} = {P_1} + 100\% $ of ${P_1}$

i.e. Momentum will increase by $ 100\%.$

Standard 11

Physics

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