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1.Units, Dimensions and Measurement
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The least count of the main scale of a vernier callipers is $1\, mm$. Its vernier scale is divided into $10$ divisions and coincide with $9$ divisions of the main scale. When jaws are touching each other, the $7$ th division of vernier scale coincides with a division of main scale and the zero of vernier scale is lying right side of the zero of main scale. When this vernier is used to measure length of a cylinder the zero of the vernier scale between $3.1\, cm$ and $3.2\, cm$ and $4^{th}$ $VSD$ coincides with a main scale division.The length of the cylinder is $.....cm$
($VSD$ is vernier scale division)
A$3.21$
B$2.99$
C$3.2$
D$3.07$
(JEE MAIN-2020)
Solution
Least count $=1 mm$ or $0.01 cm$
Zero error $=0+0.01 \times 7=0.07 cm$
Reading $=3.1+(0.01 \times 4)-0.07$
$=3.1+0.04-0.07$
$=3.1-0.03$
$=3.07 cm$
Zero error $=0+0.01 \times 7=0.07 cm$
Reading $=3.1+(0.01 \times 4)-0.07$
$=3.1+0.04-0.07$
$=3.1-0.03$
$=3.07 cm$
Standard 11
Physics
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