The length of a rod is $20\, cm$ and area of cross-section $2\,c{m^2}$. The Young's modulus of the material of wire is $1.4 \times {10^{11}}\,N/{m^2}$. If the rod is compressed by $5\, kg-wt$ along its length, then increase in the energy of the rod in joules will be
$8.57 \times {10^{ - 6}}$
$22.5 \times {10^{ - 4}}$
$9.8 \times {10^{ - 5}}$
$45.0 \times {10^{ - 5}}$
A stretched rubber has
Why do spring balances show wrong readings of weight after they have been used for a long time ?
If one end of a wire is fixed with a rigid support and the other end is stretched by a force of $10 \,N,$ then the increase in length is $0.5\, mm$. The ratio of the energy of the wire and the work done in displacing it through $1.5\, mm$ by the weight is
The strain energy stored in a body of volume $V$ due to shear strain $\phi$ is (shear modulus is $\eta$ )
Two wires of the same material (Young's modulus $Y$ ) and same length $L$ but radii $R$ and $2R$ respectively are joined end to end and a weight $W$ is suspended from the combination as shown in the figure. The elastic potential energy in the system is