The length of second's hand in a watch is | vedclass

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Question

(d) In $15\, second's$ hand rotate through $90&deg;$.

Change in velocity $\left| {\overrightarrow {\Delta v} } ight| = 2v\sin (	heta /2)$

Vedclass · Accepted Answer

$\frac{{\pi \sqrt 2 }}{{30}}cm/\sec $

Vedclass · Answer

(d) In $15\, second's$ hand rotate through $90&deg;$.

Change in velocity $\left| {\overrightarrow {\Delta v} } ight| = 2v\sin (	heta /2)$

$ = 2(r\omega )\sin (90^\circ /2)$$ = 2 	imes 1 	imes \frac{{2\pi }}{T} 	imes \frac{1}{{\sqrt 2 }}$

$ = \frac{{4\pi }}{{60\sqrt 2 }} = \frac{{\pi \sqrt 2 }}{{30}}\frac{{cm}}{{\sec }}$ [As $T = 60 \,sec$]

The length of second's hand in a watch is $1 \,cm.$ The change in velocity of its tip in $15\, seconds$ is

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