The length of the latus rectum of the ellipse | vedclass

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Question

(c) Given ellipse is $\frac{{{x^2}}}{{{{\left( {\frac{1}{3}} \right)}^2}}} + \frac{{{y^2}}}{{{{\left( {\frac{1}{2}} \right)}^2}}} = 1$

Here $b >

Vedclass · Accepted Answer

$\frac{4}{9}$

Vedclass · Answer

(c) Given ellipse is $\frac{{{x^2}}}{{{{\left( {\frac{1}{3}} ight)}^2}}} + \frac{{{y^2}}}{{{{\left( {\frac{1}{2}} ight)}^2}}} = 1$

Here $b > a$;

$	herefore $ Latus rectum $ = \frac{{2{a^2}}}{b} = \frac{{2 	imes \frac{1}{9}}}{{\frac{1}{2}}} = \frac{4}{9}$.

The length of the latus rectum of the ellipse $9{x^2} + 4{y^2} = 1$, is

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