The line, $ lx + my + n = 0$ will cut the ellipse $\frac{{{x^2}}}{{{a^2}}}$ $+$ $\frac{{{y^2}}}{{{b^2}}}$ $= 1 $ in points whose eccentric angles differ by $\pi /2$ if :
The line, $ lx + my + n = 0$ will cut the ellipse $\frac{{{x^2}}}{{{a^2}}}$ $+$ $\frac{{{y^2}}}{{{b^2}}}$ $= 1 $ in points whose eccentric angles differ by $\pi /2$ if :
- A
$a^2l^2 + b^2n^2 = 2 m^2$
- B
$a^2m^2 + b^2l^2 = 2 n^2$
- C
$a^2l^2 + b^2m^2 = 2 n^2$
- D
$a^2n^2 + b^2m^2 = 2 l^2$
Similar Questions
The foci of $16{x^2} + 25{y^2} = 400$ are
The foci of $16{x^2} + 25{y^2} = 400$ are
The locus of mid points of parts in between axes and tangents of ellipse $\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1$ will be
The locus of mid points of parts in between axes and tangents of ellipse $\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1$ will be
Find the equation for the ellipse that satisfies the given conditions: Major axis on the $x-$ axis and passes through the points $(4,\,3)$ and $(6,\,2)$
Find the equation for the ellipse that satisfies the given conditions: Major axis on the $x-$ axis and passes through the points $(4,\,3)$ and $(6,\,2)$
Find the equation of the ellipse whose vertices are $(±13,\,0)$ and foci are $(±5,\,0)$.
Find the equation of the ellipse whose vertices are $(±13,\,0)$ and foci are $(±5,\,0)$.
If $PQ$ is a double ordinate of hyperbola $\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1$ such that $OPQ$ is an equilateral triangle, $O$ being the centre of the hyperbola. Then the eccentricity $e$ of the hyperbola satisfies
If $PQ$ is a double ordinate of hyperbola $\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1$ such that $OPQ$ is an equilateral triangle, $O$ being the centre of the hyperbola. Then the eccentricity $e$ of the hyperbola satisfies