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10-2. Parabola, Ellipse, Hyperbola
easy
The distance of the point $'\theta '$on the ellipse $\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1$ from a focus is
A
$a(e + \cos \theta )$
B
$a(e - \cos \theta )$
C
$a(1 + e\cos \theta )$
D
$a(1 + 2e\cos \theta )$
Solution
(c) Focal distance of any point $P (x,y)$ on the ellipse is equal to $SP = a + ex$.
Here $x = a\cos \theta $
Here $SP = a + ae\cos \theta = a(1 + e\cos \theta )$.
Standard 11
Mathematics
