Gujarati
10-2. Parabola, Ellipse, Hyperbola
medium

The locus of the middle points of the chords of hyperbola $3{x^2} - 2{y^2} + 4x - 6y = 0$ parallel to $y = 2x$ is

A

$3x - 4y = 4$

B

$3y - 4x + 4 = 0$

C

$4x - 4y = 3$

D

$3x - 4y = 2$

Solution

(a) Let $P({x_1},{y_1})$be the middle point of the chord of the

hyperbola $3{x^2} – 2{y^2} + 4x – 6y = 0$

$\therefore$ Equation of the chord is $T = {S_1}$

i.e. $3x{x_1} – 2y{y_1} + 2(x + {x_1}) – 3(y + {y_1}) = 0$

or $(3{x_1} + 2)x – (2{y_1} + 3)y + (2{x_1} – 3{y_1}) = 0$

If this chord is parallel to line $y = 2x,$ then

${m_1} = {m_2}$==> $ – \frac{{3{x_1} + 2}}{{ – (2{y_1} + 3)}} = 2$ ==>$3{x_1} – 4{y_1} = 4$

Hence the locus of the middle point $({x_1},{y_1})$ is $3x -4y=4$.

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.