The logically equivalent preposition of $p \Leftrightarrow q$ is
The logically equivalent preposition of $p \Leftrightarrow q$ is
- [AIEEE 2012]
- A
$\left( {p \Rightarrow q} \right) \wedge \left( {q \Rightarrow p} \right)$
- B
$p \wedge q$
- C
$\left( {p \wedge q} \right) \vee \left( {q \Rightarrow p} \right)$
- D
$\left( {p \wedge q} \right) \Rightarrow \left( {q \vee p} \right)$
Similar Questions
The logical statement $(p \Rightarrow q){\wedge}(q \Rightarrow \sim p)$ is equivalent to
The logical statement $(p \Rightarrow q){\wedge}(q \Rightarrow \sim p)$ is equivalent to
- [JEE MAIN 2020]
Statement $-1 :$ $\sim (p \leftrightarrow \sim q)$ is equivalent to $p\leftrightarrow q $
Statement $-2 :$ $\sim (p \leftrightarrow \sim q)$ s a tautology
Statement $-1 :$ $\sim (p \leftrightarrow \sim q)$ is equivalent to $p\leftrightarrow q $
Statement $-2 :$ $\sim (p \leftrightarrow \sim q)$ s a tautology
- [AIEEE 2009]
Negation of “Paris in France and London is in England” is
Negation of “Paris in France and London is in England” is
Among the statements
$(S1)$: $(p \Rightarrow q) \vee((\sim p) \wedge q)$ is a tautology
$(S2)$: $(q \Rightarrow p) \Rightarrow((\sim p) \wedge q)$ is a contradiction
Among the statements
$(S1)$: $(p \Rightarrow q) \vee((\sim p) \wedge q)$ is a tautology
$(S2)$: $(q \Rightarrow p) \Rightarrow((\sim p) \wedge q)$ is a contradiction
- [JEE MAIN 2023]
Which of the following is a tautology?
Which of the following is a tautology?
- [JEE MAIN 2020]