The magnetic field of a plane electromagnetic wave is given by $\overrightarrow{ B }=3 \times 10^{-8} \cos \left(1.6 \times 10^3 x +48 \times 10^{10} t \right) \hat{ j }$, then the associated electric field will be :
The magnetic field of a plane electromagnetic wave is given by $\overrightarrow{ B }=3 \times 10^{-8} \cos \left(1.6 \times 10^3 x +48 \times 10^{10} t \right) \hat{ j }$, then the associated electric field will be :
- [NEET 2022]
- A
$3 \times 10^{-8} \cos \left(1.6 \times 10^3 x +48 \times 10^{10} t \right) \hat{ i }\,V / m$
- B
$3 \times 10^{-8} \sin \left(1.6 \times 10^3 x +48 \times 10^{10} t \right) \hat{ i }\,V / m$
- C
$9 \sin \left(1.6 \times 10^3 x -48 \times 10^{10} t \right) \hat{ k}\,V / m$
- D
$9 \cos \left(1.6 \times 10^3 x +48 \times 10^{10} t \right) \hat{ k }\, V / m$
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- [JEE MAIN 2023]