The magnetic field of a plane electromagnetic wave is given by
$\overrightarrow{ B }=2 \times 10^{-8} \sin \left(0.5 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ j } T$ The amplitude of the electric field would be.
The magnetic field of a plane electromagnetic wave is given by
$\overrightarrow{ B }=2 \times 10^{-8} \sin \left(0.5 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ j } T$ The amplitude of the electric field would be.
- [JEE MAIN 2022]
- A
$6 Vm ^{-1}$ along $x$-axis
- B
$3 Vm ^{-1}$ along $z$-axis
- C
$6 Vm ^{-1}$ along $z$-axis
- D
$2 \times 10^{-8} Vm ^{-1}$ along $z$-axis
Similar Questions
For a plane electromagnetic wave, the magnetic field at a point $x$ and time $t$ is
$\overrightarrow{ B }( x , t )=\left[1.2 \times 10^{-7} \sin \left(0.5 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ k }\right] T$
The instantaneous electric field $\overrightarrow{ E }$ corresponding to $\overrightarrow{ B }$ is : (speed of light $\left.c=3 \times 10^{8} ms ^{-1}\right)$
For a plane electromagnetic wave, the magnetic field at a point $x$ and time $t$ is
$\overrightarrow{ B }( x , t )=\left[1.2 \times 10^{-7} \sin \left(0.5 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ k }\right] T$
The instantaneous electric field $\overrightarrow{ E }$ corresponding to $\overrightarrow{ B }$ is : (speed of light $\left.c=3 \times 10^{8} ms ^{-1}\right)$
- [JEE MAIN 2020]
A plane electromagnetic wave propagating along y-direction can have the following pair of electric field $(\vec{E} )$ and magnetic field $(\overrightarrow{ B })$ components.
A plane electromagnetic wave propagating along y-direction can have the following pair of electric field $(\vec{E} )$ and magnetic field $(\overrightarrow{ B })$ components.
- [JEE MAIN 2021]
The magnetic field of a beam emerging from a filter facing a floodlight is given by B${B_0} = 12 \times {10^{ - 8}}\,\sin \,(1.20 \times {10^7}\,z - 3.60 \times {10^{15}}t)T$. What is the average intensity of the beam ?
The magnetic field of a beam emerging from a filter facing a floodlight is given by B${B_0} = 12 \times {10^{ - 8}}\,\sin \,(1.20 \times {10^7}\,z - 3.60 \times {10^{15}}t)T$. What is the average intensity of the beam ?
A radio transmitter transmits at $830\, kHz$. At a certain distance from the transmitter magnetic field has amplitude $4.82\times10^{-11}\,T$. The electric field and the wavelength are respectively
A radio transmitter transmits at $830\, kHz$. At a certain distance from the transmitter magnetic field has amplitude $4.82\times10^{-11}\,T$. The electric field and the wavelength are respectively
- [AIEEE 2012]
Even though an electric field $E$ exerts a force $qE$ on a charged particle yet the electric field of an $EM$ wave does not contribute to the radiation pressure (but transfers energy). Explain.
Even though an electric field $E$ exerts a force $qE$ on a charged particle yet the electric field of an $EM$ wave does not contribute to the radiation pressure (but transfers energy). Explain.