The magnetic field of an electromagnetic wave is given by
$\vec B = 1.6 \times {10^{ - 6}}\,\cos \,\left( {2 \times {{10}^7}z + 6 \times {{10}^{15}}t} \right)\left( {2\hat i + \hat j} \right)\frac{{Wb}}{{{m^2}}}$ The associated electric field will be
The magnetic field of an electromagnetic wave is given by
$\vec B = 1.6 \times {10^{ - 6}}\,\cos \,\left( {2 \times {{10}^7}z + 6 \times {{10}^{15}}t} \right)\left( {2\hat i + \hat j} \right)\frac{{Wb}}{{{m^2}}}$ The associated electric field will be
- [JEE MAIN 2019]
- A
$\vec E = 4.8 \times {10^{ 2}}\,\cos \,\left( {2 \times {{10}^7}z + 6 \times {{10}^{15}}t} \right)\left( { - \hat i + 2\hat j} \right)\frac{V}{m}$
- B
$\vec E = 4.8 \times {10^{ 2}}\,\cos \,\left( {2 \times {{10}^7}z + 6 \times {{10}^{15}}t} \right)\left( { - 2\hat j + 2\hat i} \right)\frac{V}{m}$
- C
$\vec E = 4.8 \times {10^{ 2}}\,\cos \,\left( {2 \times {{10}^7}z + 6 \times {{10}^{15}}t} \right)\left( {\hat i + 2\hat j} \right)\frac{V}{m}$
- D
$\vec E = 4.8 \times {10^{ 2}}\,\cos \,\left( {2 \times {{10}^7}z + 6 \times {{10}^{15}}t} \right)\left( {2\hat i + \hat j} \right)\frac{V}{m}$
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Write characteristics of electromagnetic waves.
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A radio transmitter transmits at $830\, kHz$. At a certain distance from the transmitter magnetic field has amplitude $4.82\times10^{-11}\,T$. The electric field and the wavelength are respectively
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- [AIEEE 2012]
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- [NEET 2023]
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- [KVPY 2010]
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