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8.Electromagnetic waves
easy
In an apparatus, the electric field was found to oscillate with an amplitude of $18 V/m. $ The magnitude of the oscillating magnetic field will be
A
$4 \times {10^{ - 6}}$$T$
B
$6 \times {10^{ - 8}}$$T$
C
$9 \times {10^{ - 9}}$$T$
D
$11 \times {10^{ - 11}}$$T$
Solution
(b) $c = \frac{E}{B} \Rightarrow B = \frac{E}{c} = \frac{{18}}{{3 \times {{10}^8}}} = 6 \times {10^{ – 8}}T$.
Standard 12
Physics
