Gujarati
5.Magnetism and Matter
easy

The magnetic moment of a magnet of length $10\, cm$  and pole strength $ 4.0\, Am$  will be......$A{m^2}$

A

$0.4$

B

$1.6$

C

$20$

D

$8$

Solution

(a)$M = mL = 4 \times 10 \times {10^{ – 2}} = 0.4\,A \times {m^2}$

Standard 12
Physics

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