Gujarati
5.Magnetism and Matter
easy

$10 \,cm$  लम्बी एवं $ 4.0 \,Am $  ध्रुव सामथ्र्य वाली एक चुम्बक का चुम्बकीय आघूर्ण....$A{m^2}$ होगा

A

$0.4$

B

$1.6$

C

$20$

D

$8$

Solution

$M = mL = 4 \times 10 \times {10^{ – 2}} = 0.4\,A \times {m^2}$

Standard 12
Physics

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