The mass of the body is 10.000,g and its volu | vedclass

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Question

$\frac{\Delta \rho}{\rho}= \frac{\Delta \mathrm{M}}{\mathrm{M}}+\frac{\Delta \mathrm{V}}{\mathrm{V}}=\left[\frac{0.001}{10.000}+\frac{0.01}{10.00}\rig

Vedclass · Accepted Answer

$0.0011\,g\,cm^{-3}$

Vedclass · Answer

$\frac{\Delta ho}{ho}= \frac{\Delta \mathrm{M}}{\mathrm{M}}+\frac{\Delta \mathrm{V}}{\mathrm{V}}=\left[\frac{0.001}{10.000}+\frac{0.01}{10.00}ight]=10^{-4}+10^{-3}$

$\quad=0.1 	imes 10^{-3}+10^{-3} =1.1 	imes 10^{-3}$

$\Delta ho=1.1 	imes 10^{-3} 	imes \frac{10.000}{10.00}$

$=1.1 	imes 10^{-3}$

$=0.0011\,g\,cm^{-3}$

The mass of the body is $10.000\,g$ and its volume is $10.00\,cm^3$. If the measured values are expressed upto the correct significant figures, the maximum error in the measurement of density is

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