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7.Gravitation
hard
The masses $m$ in fig. $(A)$ and $(B)$ are identical. The gravitational potential energy in the two cases are $U_A$ and $U_B$. Then
A
$U_A = U_B \neq 0$
B
$U_A < U_B$
C
$U_A > U_B$
D
$U_A = U_B = 0$
Solution
$\mathrm{U}_{\mathrm{A}}=\frac{-\mathrm{Gm}^{2}}{\mathrm{d}}-\frac{\mathrm{Gm}^{2}}{\mathrm{d}}-\frac{\mathrm{Gm}^{2}}{\sqrt{2 \mathrm{d}}}$
$\mathrm{U}_{\mathrm{B}}=\frac{-\mathrm{Gm}^{2}}{\mathrm{d}}-\frac{\mathrm{Gm}^{2}}{\mathrm{d}}-\frac{\mathrm{Gm}^{2}}{2 \mathrm{d}}$
$\therefore \mathrm{U}_{\mathrm{A}}<\mathrm{U}_{\mathrm{B}}$
Standard 11
Physics
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