Maximum horizontal range of a projectile is 160, m . When projectile is thrown with same

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3-2.Motion in Plane

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The maximum horizontal range of a projectile is $160\, m$. When the projectile is thrown with the same speed at an elevation of $30^o$ from the horizontal, it will reach to the maximum height of ......... $m$

A

$20$

B

$40$

C

$80 $

D

$160$

Solution

$\mathrm{R}=\frac{\mathrm{u}^{2} \sin 2 \theta}{\mathrm{g}}$ so that $\mathrm{R}_{\max }=\frac{\mathrm{u}^{2}}{\mathrm{g}}=160 \mathrm{m}$

$\mathrm{H}_{\max }=\frac{\mathrm{u}^{2} \sin ^{2} \theta}{2 \mathrm{g}}$

$=\frac{1}{2} \times 160 \times \sin ^{2} 30^{\circ}=20$

Standard 11

Physics

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