Gujarati
3-2.Motion in Plane
medium

The maximum horizontal range of a projectile is $400\, m$. The maximum value of height attained by it will be    ......... $m$

A

$100$

B

$200 $

C

$400$

D

$800$

Solution

(b) ${R_{\max }} = \frac{{{u^2}}}{g}$ $ = 400m$$({\rm{For\, }}\theta = 45^\circ )$

${H_{\max }} = \frac{{{u^2}}}{{2g}} = \frac{{400}}{2} = 200m$ $({\rm{For\, }}\theta = 90^\circ )$

Standard 11
Physics

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