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3-2.Motion in Plane
medium
The maximum horizontal range of a projectile is $400\, m$. The maximum value of height attained by it will be ......... $m$
A
$100$
B
$200 $
C
$400$
D
$800$
Solution
(b) ${R_{\max }} = \frac{{{u^2}}}{g}$ $ = 400m$$({\rm{For\, }}\theta = 45^\circ )$
${H_{\max }} = \frac{{{u^2}}}{{2g}} = \frac{{400}}{2} = 200m$ $({\rm{For\, }}\theta = 90^\circ )$
Standard 11
Physics
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