The maximum horizontal range of a projectile | vedclass

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Question

(b) ${R_{\max }} = \frac{{{u^2}}}{g}$ $ = 400m$$({m{For\, }}	heta = 45^\circ )$

${H_{\max }} = \frac{{{u^2}}}{{2g}} = \frac{{400}}{2} = 200m$ $(

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(b) ${R_{\max }} = \frac{{{u^2}}}{g}$ $ = 400m$$({m{For\, }}	heta = 45^\circ )$

${H_{\max }} = \frac{{{u^2}}}{{2g}} = \frac{{400}}{2} = 200m$ $({m{For\, }}	heta = 90^\circ )$

The maximum horizontal range of a projectile is $400\, m$. The maximum value of height attained by it will be ......... $m$

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