The mean free path of electrons in a metal is $4 \times 10^{-8} \;m$. The electric field which can give on an average $2 \;eV$ energy to an electron in the metal will be in units of $V / m$
The mean free path of electrons in a metal is $4 \times 10^{-8} \;m$. The electric field which can give on an average $2 \;eV$ energy to an electron in the metal will be in units of $V / m$
- [AIPMT 2009]
- A
$8 \times 10^7$
- B
$5 \times 10^7$
- C
$5 \times 10^{-11}$
- D
$8 \times 10^{-11}$
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- [AIPMT 2005]
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