Gujarati
7.Gravitation
medium

The mean radius of the earth's orbit round the sun is $1.5 \times {10^{11}}$. The mean radius of the orbit of mercury round the sun is $6 \times {10^{10}}\,m$. The mercury will rotate around the sun in

A

A year

B

Nearly $4$ years

C

Nearly $\frac{1}{4}$ year

D

$2.5$ years

Solution

(c) $\frac{{{T_{{\rm{mercury}}}}}}{{{T_{{\rm{earth}}}}}} = {\left( {\frac{{{r_{{\rm{mercury}}}}}}{{{r_{{\rm{earth}}}}}}} \right)^{3/2}} = {\left( {\frac{{6 \times {{10}^{10}}}}{{1.5 \times {{10}^{11}}}}} \right)^{3/2}} = \frac{1}{4}$ (approx.)

$\therefore$ ${T_{{\rm{mercury}}}} = \frac{1}{4}{\rm{ year}}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.