The momentum of a photon with energy $20\, eV$ is
$10.0 \times {10^{ - 27}}\,\frac{{kg \times m}}{s}$
$10.95 \times {10^{ - 27}}\,\frac{{kg \times m}}{s}$
$10.66 \times {10^{ - 27}}\,\frac{{kg \times m}}{s}$
$10.2 \times {10^{ - 27}}\,\frac{{kg \times m}}{s}$
When radiation of wavelength $\lambda $ is incident on a metallic surface, the stopping potential is $4.8\, volts$. If the same surface is illuminated with radiation of double the wavelength, then the stopping potential becomes $1.6\, volts$. Then the threshold wavelength for the surface is
A $10\, kW$ transmitter emits radio waves of wavelength $500\, m$. The number of photons emitted per second by the transmitter is of the order of
A $200\, W$ sodium street lamp emits yellow light of wavelength $0.6\, \mu m$. Assuming it to be $25\%$ efficient in converting electrical energy to light, the number of photon of yellow light it emits per second is
Energy of a quanta of frequency ${10^{15}}Hz$ and $h = 6.6 \times {10^{ - 34}}J{\rm{ - }}\sec $ will be
Photo cell is a device to