Motion of a simple pendulum excuting S.H.M . is represented by following equation. Y = A sin (π t +

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13.Oscillations

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The motion of a simple pendulum excuting $S.H.M$. is represented by following equation.

$Y = A \sin (\pi t +\phi)$, where time is measured in $second$.

The length of pendulum is .............$cm$

A

$97.23$

B

$25.3$

C

$99.4$

D

$406.1$

(JEE MAIN-2022)

Solution

$\omega=\sqrt{\frac{ g }{\ell}}=\pi$

$\frac{ g }{\ell}=\pi^{2} \Rightarrow \ell=\frac{ g }{\pi^{2}}$

$\ell=\frac{980}{\pi^{2}} \approx 99.4 \,cm$

Standard 11

Physics

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