The negation of the Boolean expression x | vedclass

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Question

$p \leftrightarrow q \equiv( p \rightarrow q ) \wedge( q \rightarrow p )$

$x \leftrightarrow \sim y \equiv( x \rightarrow \sim y ) \wedge(\sim y \r

Vedclass · Accepted Answer

$(x \wedge y) \vee(\sim x \wedge \sim y)$

Vedclass · Answer

$p \leftrightarrow q \equiv( p \rightarrow q ) \wedge( q \rightarrow p )$

$x \leftrightarrow \sim y \equiv( x \rightarrow \sim y ) \wedge(\sim y \rightarrow x )$

$\because( p \rightarrow q \equiv \sim p \vee q )$

$x \leftrightarrow \sim y \equiv(\sim x \vee \sim y ) \wedge( y \vee x )$

$\sim( x \leftrightarrow \sim y ) \equiv( x \wedge y ) \vee(\sim x \wedge \sim y )$

The negation of the Boolean expression $x \leftrightarrow \sim y$ is equivalent to

Similar Questions

The statement $(p \wedge(\sim q) \vee((\sim p) \wedge q) \vee((\sim p) \wedge(\sim q))$ is equivalent to

$\sim (p \vee q) \vee (\sim p \wedge q)$ is logically equivalent to

The negation of the expression $q \vee((\sim q) \wedge p)$ is equivalent to

Which of the following is a statement

Statement $-1$ : The statement $A \to (B \to A)$ is equivalent to $A \to \left( {A \vee B} \right)$.

Statement $-2$ : The statement $ \sim \left[ {\left( {A \wedge B} \right) \to \left( { \sim A \vee B} \right)} \right]$ is a Tautology