The negation of the Boolean expression $x \leftrightarrow \sim y$ is equivalent to
The negation of the Boolean expression $x \leftrightarrow \sim y$ is equivalent to
- [JEE MAIN 2020]
- A
$(\sim x \wedge y) \vee(\sim x \wedge \sim y)$
- B
$(x \wedge \sim y) \vee(\sim x \wedge y)$
- C
$(x \wedge y) \vee(\sim x \wedge \sim y)$
- D
$(x \wedge y) \wedge(\sim x \vee \sim y)$
Similar Questions
The negation of the statement
''If I become a teacher, then I will open a school'', is
The negation of the statement
''If I become a teacher, then I will open a school'', is
Consider the following three statements :
$P : 5$ is a prime number.
$Q : 7$ is a factor of $192$.
$R : L.C.M.$ of $5$ and $7$ is $35$.
Then the truth value of which one of the following statements is true?
Consider the following three statements :
$P : 5$ is a prime number.
$Q : 7$ is a factor of $192$.
$R : L.C.M.$ of $5$ and $7$ is $35$.
Then the truth value of which one of the following statements is true?
- [JEE MAIN 2019]
The Boolean expression $( p \Rightarrow q ) \wedge( q \Rightarrow \sim p )$ is equivalent to :
The Boolean expression $( p \Rightarrow q ) \wedge( q \Rightarrow \sim p )$ is equivalent to :
- [JEE MAIN 2021]
The false statement in the following is
The false statement in the following is
Statement $-1$ : $ \sim \left( {p \leftrightarrow \, \sim q} \right)$ is equivalent to $p \leftrightarrow q$
Statement $-2$ : $ \sim \left( {p \leftrightarrow \, \sim q} \right)$ is a tautology.
Statement $-1$ : $ \sim \left( {p \leftrightarrow \, \sim q} \right)$ is equivalent to $p \leftrightarrow q$
Statement $-2$ : $ \sim \left( {p \leftrightarrow \, \sim q} \right)$ is a tautology.