The negation of $(p \wedge(\sim q)) \vee(\sim p)$ is equivalent to
$p \wedge q$
$p \wedge(\sim q )$
$p ^{\wedge}\left( q ^{\wedge}(\sim p )\right)$
$p \vee( q \vee(\sim p ))$
Let $p, q, r$ denote arbitrary statements. Then the logically equivalent of the statement $p\Rightarrow (q\vee r)$ is
Consider the following statements :
$A$ : Rishi is a judge.
$B$ : Rishi is honest.
$C$ : Rishi is not arrogant.
The negation of the statement "if Rishi is a judge and he is not arrogant, then he is honest" is
Negation of statement "If I will go to college, then I will be an engineer" is -
The conditional $(p \wedge q) \Rightarrow p$ is :-
The negation of the compound statement $^ \sim p \vee \left( {p \vee \left( {^ \sim q} \right)} \right)$ is