The negative of the statement $\sim p \wedge(p \vee q)$ is
$\sim p \vee q$
$p \vee \sim q$
$\sim p \wedge q$
$p \wedge \sim q$
$\sim p \wedge q$ is logically equivalent to
The propositions $(p \Rightarrow \;\sim p) \wedge (\sim p \Rightarrow p)$ is a
Let $p , q , r$ be three logical statements. Consider the compound statements $S _{1}:((\sim p ) \vee q ) \vee((\sim p ) \vee r ) \text { and }$ and $S _{2}: p \rightarrow( q \vee r )$ Then, which of the following is NOT true$?$
Which of the following is not a statement
The negation of $ \sim s \vee \left( { \sim r \wedge s} \right)$ is equivalent to :