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3 and 4 .Determinants and Matrices
easy
પ્રત્યેક ઘટક $0$ અથવા $1$ હોય તેવા $3 \times 3$ કક્ષાવાળા શ્રેણિકની સંખ્યા ............ .
A
$512$
B
$18$
C
$81$
D
$27$
Solution
The given matrix of the order $3 \times 3$ has $9$ elements and each of these elements can be either $0$ or $1$.
Now, each of the $9$ elements can be filled in two possible ways.
Therefore, by the multiplication principle, the required number of possible matrices is $2^{9}=512$.
Standard 12
Mathematics