3 and 4 .Determinants and Matrices
easy

પ્રત્યેક ઘટક $0$ અથવા $1$ હોય તેવા $3 \times 3$ કક્ષાવાળા શ્રેણિકની સંખ્યા ............ .

A

$512$

B

$18$

C

$81$

D

$27$

Solution

The given matrix of the order $3 \times 3$ has $9$ elements and each of these elements can be either $0$ or $1$.

Now, each of the $9$ elements can be filled in two possible ways.

Therefore, by the multiplication principle, the required number of possible matrices is $2^{9}=512$.

Standard 12
Mathematics

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