Number of all possible matrices of order 3 × 3 with each entry 0 or 1 is :

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3 and 4 .Determinants and Matrices

easy

The number of all possible matrices of order $3 \times 3$ with each entry $0$ or $1$ is :

A

$512$

B

$18$

C

$81$

D

$27$

Solution

The given matrix of the order $3 \times 3$ has $9$ elements and each of these elements can be either $0$ or $1$.

Now, each of the $9$ elements can be filled in two possible ways.

Therefore, by the multiplication principle, the required number of possible matrices is $2^{9}=512$.

Standard 12

Mathematics

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