- Home
- Standard 12
- Mathematics
समीकरण $\left|\begin{array}{lll}\cos x & \sin x & \sin x \\ \sin x & \cos x & \sin x \\ \sin x & \sin x & \cos x\end{array}\right|=0$, के अंतराल $\left[-\frac{\pi}{4}, \frac{\pi}{4}\right]$ में भिन्न वास्तविक मूलों की संख्या है
$1$
$4$
$2$
$3$
Solution
$\begin{array}{*{20}{c}}
{\cos x}&{\sin x}&{\sin x}\\
{\sin x}&{\cos x}&{\sin x}\\
{\sin x}&{\sin x}&{\cos x}
\end{array} = 0$
${R_1} \to {R_1} – {R_2}$
${R_2} \to {R_2} – {R_3}$
$\begin{array}{*{20}{c}}
{\cos x – \sin x}&{\sin x – \cos x}&0\\
0&{\cos x – \sin x}&{\sin x – \cos x}\\
{\sin x}&{\sin x}&{\cos x}
\end{array} = 0$
${C_2} \to {C_2} + {C_3}$
$\begin{array}{*{20}{c}}
{\cos x – \sin x}&{\sin x – \cos x}&0\\
0&0&{\sin x – \cos x}\\
{\sin x}&{\sin x}&{\cos x}
\end{array} = 0$
Expanding using second row
$2\sin x{\left( {\sin x – \cos x} \right)^2} = 0$
$\sin x = 0$ or $\sin x = \cos x$
$x = 0$ or $x = \frac{\pi }{4}$