Gujarati
1. Electric Charges and Fields
easy

$1.6\,C$ आवेश में इलेक्ट्रॉनों की संख्या होगी

A

${10^{19}}$

B

${10^{20}}$

C

$1.1 \times {10^{19}}$

D

$1.1 \times {10^{2}}$

Solution

$n = \frac{q}{e} = \frac{{1.6}}{{1.6 \times {{10}^{ – 19}}}} = {10^{19}}$

Standard 12
Physics

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