The number of four letter words that can be f | vedclass

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Question

If all four letters are different then the number of words $^5{C_4} 	imes 4! = 120$

If two letters are $R$ and other two different letters ar

Vedclass · Accepted Answer

$270$

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If all four letters are different then the number of words $^5{C_4} 	imes 4! = 120$

If two letters are $R$ and other two different letters are chosen from $B,A,C,K$ then the number of words ${ = ^4}{C_2} 	imes \frac{{4!}}{{2!}} = 72$

If two letter are $A$ and other two different letters are chosen from $B,R,C,K$ then the number of words ${ = ^4}{C_2} 	imes \frac{{4!}}{{2!}} = 72$

$D(x,y,z) = \left( {\frac{6}{3},\frac{{13}}{3},\frac{{18}}{3}} ight)$

Therefore, position vector of poin 

$P = \frac{1}{2}(6i + 13j + 18k)$

The number of four letter words that can be formed using the letters of the word $BARRACK$ is

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