4-1.Complex numbers
medium

$a$ ની કેટલી વાસ્તવિક કિમત માટે સમીકરણ ${a^2} - 2a\sin x + 1 = 0$ કરે.

A

$0$

B

$1$

C

$2$

D

અનંત

Solution

(c)Given equation ${a^2} – 2a\sin x + 1 = 0$
$\therefore $ $a = \frac{{2\sin x \pm \sqrt {4{{\sin }^2}x – 4} }}{2}$ $ = \sin x \pm \sqrt { – (1 – {{\sin }^2}x)} $
$a = \sin x \pm i\cos x$
If $x = \frac{\pi }{2}$==> $a = 1,$$x = {270^o}$==> $a = – 1$.

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.