Pair of straight lines x^2 - 4xy + y^2 = 0 together with line x + y + 4 = 0 form a triangle which is

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9.Straight Line

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The pair of straight lines $x^2 - 4xy + y^2 = 0$ together with the line $x + y + 4 = 0$ form a triangle which is :

A

right angled but not isosceles

B

right isosceles

C

scalene

D

equilateral

Solution

consider angle bet $x^2 – 4xy + y^2 = 0$

Let $\frac{y}{x}$ $= m$

$\therefore\,\,\,m^2 – 4m + 1 = 0$

$\therefore\,\,\,m =$ $2 \pm \sqrt 3 $

$\therefore \Delta \,is\,equlated$

Standard 11

Mathematics

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