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5.Magnetism and Matter
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When $2 $ $amperes$ current is passed through a tangent galvanometer, it gives a deflection of $30^o$. For $60^o$ deflection, the current must be........$amp$
A
$1 $
B
$2\sqrt 3$
C
$4$
D
$6 $
Solution
(d)$i \propto \tan \phi \Rightarrow \frac{{{i_1}}}{{{i_2}}} = \frac{{\tan {\phi _1}}}{{\tan {\phi _2}}}$$ \Rightarrow \frac{2}{{{i_2}}} = \frac{{\tan 30^\circ }}{{\tan 60^\circ }} \Rightarrow {i_2} = 6\;amp$
Standard 12
Physics