Pitch and number of divisions, on circular scale, for a given screw gauge are 0.5,mm and 100 respect

English

Gujarati

Hindi

1.Units, Dimensions and Measurement

hard

The pitch and the number of divisions, on the circular scale, for a given screw gauge are $0.5\,mm$ and $100$ respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies $3$ divisions below the mean line. The readings of the main scale and the circular scale for a thin sheet, are $5.5\,mm$ and $48$ respectively, the thickness of this sheet is

A

$5.755\,mm$

B

$5.950\,mm$

C

$5.725\,mm$

D

$5.740\,mm$

(JEE MAIN-2019)

Solution

$L C=\frac{P i t c h}{\text {No.ofdivision}}$

$L C=0.5 \times 10^{-2} mm$

+ve error $=3 \times 0.5 \times 10^{-2} mm$

$=1.5 \times 10^{-2} mm =0.015 mm$

Reading $= MSR + CSR -(+\text { ve error })$

$=5.5 m m+\left(48 \times 0.5 \times 10^{-2}\right)-0.015$

$=5.5+0.24-0.015=5.725 mm$

Standard 11

Physics

Share

Similar Questions

A student measured the diameter of a small steel ball using a screw gauge of least count $0.001\, cm.$ The main scale reading is $5\, mm$ and zero of circular scale division coincides with $25$ divisions above the reference level. If screw gauge has a zero error of $-0.004 \,cm,$ the correct diameter of the ball is

medium

(NEET-2018)

In a vernier callipers, $10$ divisions of vernier scale coincides with $9$ divisions of main scale, the least count of which is $0.1\,cm$. If in the measurement of inner diameter of cylinder zero of vernier scale lies between $1.3\,cm$ and $1.4\, cm$ of main scale and $2^{nd}$ division of vernier scale coincides with main scale division then diameter will be ………. $cm$

medium

Diagrams show readings of a screw gauge. figure $(i)$ shows the zero error reading when the screw gauge is closed, figure $(ii)$ the reading when the screw gauge is being used to measure the diameter of a ball-bearing. What is the diameter of the ball-bearing in $mm$? There are $50$ divisions on circular scale

medium

Two full turns of the circular scale of screw gauge cover a distance of $1\,mm$ on scale. The total number of divisions on circular scale is $50$. Further, it is found that screw gauge has a zero error of $+0.03\,mm$. While measuring the diameter of a thin wire a student notes the main scale reading of $3\,mm$ and the number of circular scale division in line, with the main scale is $35$. The diameter of the wire is ………. $mm$

medium

Using screw gauge of pitch $0.1$ $cm$ and $50$ divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as

medium

(JEE MAIN-2020)