Radical axis of pair of circle {x^2} + {y^2} = 144 and {x^2} + {y^2} - 15x + 12y = 0 is

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10-1.Circle and System of Circles

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The radical axis of the pair of circle ${x^2} + {y^2} = 144$ and ${x^2} + {y^2} - 15x + 12y = 0$ is

A

$15x - 12y = 0$

B

$3x - 2y = 12$

C

$5x - 4y = 48$

D

None of these

Solution

(c) The radical axis of the circle ${S_1} = 0$ and ${S_2} = 0$ is ${S_1} – {S_2} = 0$

$\therefore \;({x^2} + {y^2} – 144) – ({x^2} + {y^2} – 15x + 12y) = 0$

$ \Rightarrow 15x – 12y – 144 = 0 $

$\Rightarrow 5x – 4y = 48$.

Standard 11

Mathematics

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