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13.Nuclei
medium
The radioactivity of a certain radioactive element drops to $1/64$ of its initial value in $30\, seconds$. Its half life is .........$seconds$
A
$2 $
B
$4 $
C
$5$
D
$6$
Solution
(c) $N = {N_0}{\left( {\frac{1}{2}} \right)^{t/T}} $
$\Rightarrow \frac{{{N_0}}}{{64}} = {N_0}{\left( {\frac{1}{2}} \right)^{30/T}}$
$ \Rightarrow T = \frac{{30}}{6} = 5\sec $
Standard 12
Physics