The radius of R of a nucleus of mass number A | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$ho_{	ext {nucleus }}=\frac{	ext { mass }}{	ext { volume }}=\frac{A}{(4 / 3) \pi r_{0}^{3} A}=\frac{3}{4 \pi r_{0}^{3}}=2.3 	imes 10^{17} kg / m

Vedclass · Accepted Answer

$10^{17} \;kg m ^{-3}$

Vedclass · Answer

$ho_{	ext {nucleus }}=\frac{	ext { mass }}{	ext { volume }}=\frac{A}{(4 / 3) \pi r_{0}^{3} A}=\frac{3}{4 \pi r_{0}^{3}}=2.3 	imes 10^{17} kg / m^{3}$

The radius of $R$ of a nucleus of mass number $A$ can be estimated by the formula $R =\left(1.3 \times 10^{-15}\right) A ^{1 / 3}\, m .$ It follows that the mass density of a nucleus is of the order of

$\left( M _{\text {prot. }} \cong M _{\text {neut. }}=1.67 \times 10^{-27} kg \right)$

Similar Questions

A heavy nucleus is unstable for any value of $\frac{N}{P}$ because

The charge density in a nucleus varies with distance from the centre of the nucleus according to the curve in Fig.

What percentage of the mass of the nucleus is the mass of the nucleus ?

Two nuclei have their mass numbers in the ratio of $1 : 3.$ The ratio of their nuclear densities would be

Given the mass of iron nucleus as $55.85\,u$ and $A=56$, find the nuclear density?

The radius of $R$ of a nucleus of mass number $A$ can be estimated by the formula $R =\left(1.3 \times 10^{-15}\right) A ^{1 / 3}\, m .$ It follows that the mass density of a nucleus is of the order of $\left( M _{\text {prot. }} \cong M _{\text {neut. }}=1.67 \times 10^{-27} kg \right)$