Radius of a metallic sphere if its capacitance is 1/9,F , is

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2. Electric Potential and Capacitance

easy

The radius of a metallic sphere if its capacitance is $1/9\,F$, is

A

${10^6}\,m$

B

${10^7}\,m$

C

${10^9}\,m$

D

${10^8}\,m$

Solution

(c) $C = 4\pi {\varepsilon _0}R$, $R = \frac{C}{{4\pi {\varepsilon _0}}}$ $==>$ $R = (1/9) \times 9 \times {10^9} = {10^9}\,m$

Standard 12

Physics

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