- Home
- Standard 12
- Physics
2. Electric Potential and Capacitance
easy
$1/9\,F$ धारिता वाले एक धात्विक गोले की त्रिज्या होगी
A
${10^6}\,m$
B
${10^7}\,m$
C
${10^9}\,m$
D
${10^8}\,m$
Solution
$C = 4\pi {\varepsilon _0}R$, $R = \frac{C}{{4\pi {\varepsilon _0}}}$
$R = (1/9) \times 9 \times {10^9} = {10^9}\,m$
Standard 12
Physics