The radius of circular path of an electron when subjected to a perpendicular magnetic field is
$\frac{{mv}}{{Be}}$
$\frac{{me}}{{Be}}$
$\frac{{mE}}{{Be}}$
$\frac{{Be}}{{mv}}$
(a)
Proton, deuteron and alpha particle of same kinetic energy are moving in circular trajectories in a constant magnetic field. The radii of proton, deuteron and alpha particle are respectively $r_p, r_d$ and $r_{\alpha}$ Which one of the following relation is correct?
A particle of mass $m$ and charge $q$, accelerated by a potential difference $V$ enters a region of a uniform transverse magnetic field $B$. If $d$ is the thickness of the region of $B$, the angle $\theta$ through which the particle deviates from the initial direction on leaving the region is given by
If a charged particle enters perpendicularly in the uniform magnetic field then
An electron is moving along $+x$ direction. To get it moving along an anticlockwise circular path in $x-y$ plane, magnetic field applied along
A charged particle initially at rest at $O$,when released follows a trajectory as shown alongside. Such a trajectory is possible in the presence of
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