The radius of nucleus of silver (atomic number $=$ $47$) is $3.4 \times {10^{ - 14}}\,m$. The electric potential on the surface of nucleus is $(e = 1.6 \times {10^{ - 19}}\,C)$
The radius of nucleus of silver (atomic number $=$ $47$) is $3.4 \times {10^{ - 14}}\,m$. The electric potential on the surface of nucleus is $(e = 1.6 \times {10^{ - 19}}\,C)$
- A
$1.99 \times {10^6}\,volt$
- B
$2.9 \times {10^6}\,volt$
- C
$4.99 \times {10^6}\,volt$
- D
$0.99 \times {10^6}\,volt$
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