The ratio activity of an element becomes frac | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) $A = {A_0}{\left( {\frac{1}{2}} \right)^{\frac{t}{{{T_{1/2}}}}}} $

$\Rightarrow \frac{1}{{64}} = {\left( {\frac{1}{2}} \right)^{\frac{{60}}{{{T

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(b) $A = {A_0}{\left( {\frac{1}{2}} \right)^{\frac{t}{{{T_{1/2}}}}}} $

$\Rightarrow \frac{1}{{64}} = {\left( {\frac{1}{2}} \right)^{\frac{{60}}{{{T_{1/2}}}}}}$

$ \Rightarrow {\left( {\frac{1}{2}} \right)^6} = {\left( {\frac{1}{2}} \right)^{\frac{{60}}{{{T_{1/2}}}}}} $

$\Rightarrow {T_{1/2}} = 10\sec $

The ratio activity of an element becomes $\frac{{1}}{{64}} th$ of its original value in $60\, sec$. Then the half life period is ............$sec$

Similar Questions

Write and derive the law of radioactivity decay.

$99 \%$ of a radioactive element will decay between

The half-life of radium is about $1600$ years. Of $100\, g$ of radium existing now, $25\, g$ will remain unchanged after .......... $years$

If $10\%$ of a radioactive material decays in $5$ days, then the amount of original material left after $20$ days is approximately ...............$\%$

An archaeologist analyses the wood in a prehistoric structure and finds that ${C^{14}}$ (Half life $= 5700\, years$) to ${C^{12}} $ is only one- fourth of that found in the cells buried plants. The age of the wood is about ........$years$