Ratio of maximum and minimum magnitudes of resultant of two vector vec a and vec b is 3 : 1 . Now |

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3-1.Vectors

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The ratio of maximum and minimum magnitudes of the resultant of two vector $\vec a$ and $\vec b$ is $3 : 1$. Now $| \vec a |$ is equal to

A

$| \vec b |$

B

$2| \vec b |$

C

$3| \vec b |$

D

$4| \vec b |$

Solution

$\frac{{a + b}}{{a – b}} = \frac{3}{1} \Rightarrow \,a = 2b$

Standard 11

Physics

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