10-2.Transmission of Heat
medium

The ratio of thermal conductivity of two rods of different material is $5 : 4$ . The two rods of same area of cross-section and same thermal resistance will have the lengths in the ratio

A

$4:5$

B

$9:1$

C

$1:9$

D

$5:4$

Solution

(d) Given ${A_1} = {A_2}$ and $\frac{{{K_1}}}{{{K_2}}} = \frac{5}{4}$

$\because$${R_1} = {R_2} $  $\Rightarrow  \frac{{{l_1}}}{{{K_1}A}} = \frac{{{l_2}}}{{{K_2}A}}$

==> $\frac{{{l_1}}}{{{l_2}}} = \frac{{{K_1}}}{{{K_2}}} = \frac{5}{4}.$

Standard 11
Physics

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