The relative error in resistivity of a materi | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\mathrm{R}=\frac{\rho \ell}{\mathrm{A}}$

$\rho=\frac{\mathrm{RA}}{\ell}=\frac{\mathrm{R} \pi \mathrm{r}^{2}}{\ell}=\frac{\pi \mathrm{d}^{2} \mathr

Vedclass · Accepted Answer

$0.04$

Vedclass · Answer

$\mathrm{R}=\frac{\rho \ell}{\mathrm{A}}$

$\rho=\frac{\mathrm{RA}}{\ell}=\frac{\mathrm{R} \pi \mathrm{r}^{2}}{\ell}=\frac{\pi \mathrm{d}^{2} \mathrm{R}}{4 \ell}$

$\frac{\Delta \rho}{\rho}=\frac{\Delta \mathrm{R}}{\mathrm{R}}+\frac{\Delta \mathrm{d}}{\mathrm{d}}+\frac{\Delta \ell}{\ell}$

The relative error in resistivity of a material where

resistance $= 1.05 \pm 0.01\, \Omega$

diameter $= 0.60 \pm 0.01\, mm$

length $= 75.3 \pm 0.1 \,cm$ is

Similar Questions

The length and breadth of a rectangle are $(5.7 \pm 0.1) cm$ and $(3.4 \pm 0.2) cm$, respectively. Calculate the area of rectangle with error limits.

The radius ( $\mathrm{r})$, length $(l)$ and resistance $(\mathrm{R})$ of a metal wire was measured in the laboratory as
$\mathrm{r}=(0.35 \pm 0.05) \mathrm{cm}$
$\mathrm{R}=(100 \pm 10) \mathrm{ohm}$
$l=(15 \pm 0.2) \mathrm{cm}$
The percentage error in resistivity of the material of the wire is :

Write type of error in measurement of physical quantity and explain.

In the density measurement of a cube, the mass and edge length are measured as $(10.00 \pm 0.10)\,\,kg\,$ and $(0.10 \pm 0.01)\,\,m\,$ respectively. The error in the measurement of density is

The percentage error in the measurement of $g$ is $.....\%$ (Given that $g =\frac{4 \pi^2 L }{ T ^2}, L =(10 \pm 0.1)\,cm$, $T =(100 \pm 1)\,s )$

The relative error in resistivity of a material where resistance $= 1.05 \pm 0.01\, \Omega$ diameter $= 0.60 \pm 0.01\, mm$ length $= 75.3 \pm 0.1 \,cm$ is