The resultant of two forces 3P and 2P is R. I | vedclass

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Question

(b) ${R^2} = {(3P)^2} + {(2P)^2} + 2 	imes 3P 	imes 2P 	imes \cos 	heta $&hellip;(i)

${(2R)^2} = {(6P)^2} + {(2P)^2} + 2 	imes 6P 	imes 2P

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(b) ${R^2} = {(3P)^2} + {(2P)^2} + 2 	imes 3P 	imes 2P 	imes \cos 	heta $&hellip;(i)

${(2R)^2} = {(6P)^2} + {(2P)^2} + 2 	imes 6P 	imes 2P 	imes \cos 	heta $&hellip;(ii)

by solving (i) and (ii), $\cos 	heta = - 1/2$

$&rArr;$ $	heta = 120^\circ $

The resultant of two forces $3P$ and $2P$ is $R$. If the first force is doubled then the resultant is also doubled. The angle between the two forces is ........... $^o$

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