Two forces with equal magnitudes $F$ act on a body and the magnitude of the resultant force is $F/3$. The angle between the two forces is
Two forces with equal magnitudes $F$ act on a body and the magnitude of the resultant force is $F/3$. The angle between the two forces is
- A
${\cos ^{ - 1}}\left( { - \frac{{17}}{{18}}} \right)$
- B
${\cos ^{ - 1}}\left( { - \frac{1}{3}} \right)$
- C
${\cos ^{ - 1}}\left( {\frac{2}{3}} \right)$
- D
${\cos ^{ - 1}}\left( {\frac{8}{9}} \right)$
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The resultant of these forces $\overrightarrow{O P}, \overrightarrow{O Q}, \overrightarrow{O R}, \overrightarrow{O S}$ and $\overrightarrow{{OT}}$ is approximately $\ldots \ldots {N}$.
[Take $\sqrt{3}=1.7, \sqrt{2}=1.4$ Given $\hat{{i}}$ and $\hat{{j}}$ unit vectors along ${x}, {y}$ axis $]$
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