Two forces with equal magnitudes $F$ act on a body and the magnitude of the resultant force is $F/3$. The angle between the two forces is
${\cos ^{ - 1}}\left( { - \frac{{17}}{{18}}} \right)$
${\cos ^{ - 1}}\left( { - \frac{1}{3}} \right)$
${\cos ^{ - 1}}\left( {\frac{2}{3}} \right)$
${\cos ^{ - 1}}\left( {\frac{8}{9}} \right)$
Two forces are such that the sum of their magnitudes is $18 \,N$ and their resultant is perpendicular to the smaller force and magnitude of resultant is $12\, N$. Then the magnitudes of the forces are
Which pair of the following forces will never give resultant force of $2\, N$
A body is at rest under the action of three forces, two of which are ${\vec F_1} = 4\hat i,\,{\vec F_2} = 6\hat j,$ the third force is
The sum of three forces ${\vec F_1} = 100\,N,{\vec F_2} = 80\,N$ and ${\vec F_3} = 60\,N$ acting on a particle is zero. The angle between $\vec F_1$ and $\vec F_2$ is nearly .......... $^o$