Two forces with equal magnitudes $F$ act on a body and the magnitude of the resultant force is $F/3$. The angle between the two forces is
${\cos ^{ - 1}}\left( { - \frac{{17}}{{18}}} \right)$
${\cos ^{ - 1}}\left( { - \frac{1}{3}} \right)$
${\cos ^{ - 1}}\left( {\frac{2}{3}} \right)$
${\cos ^{ - 1}}\left( {\frac{8}{9}} \right)$
When vector $\overrightarrow{ A }=2 \hat{ i }+3 \hat{ j }+2 \hat{ k }$ is subtracted from vector $\vec{B}$, it gives a vector equal to $2 \hat{j}$. Then the magnitude of vector $\vec{B}$ will be:
Find the resultant of three vectors $\overrightarrow {OA} ,\,\overrightarrow {OB} $ and $\overrightarrow {OC} $ shown in the following figure. Radius of the circle is $R$.
Two forces ${F_1} = 1\,N$ and ${F_2} = 2\,N$ act along the lines $x = 0$ and $y = 0$ respectively. Then the resultant of forces would be
If a particle moves from point $P (2,3,5)$ to point $Q (3,4,5)$. Its displacement vector be